[Bug 47159] New: widl ignores calling convention when declaring functions with extraneous parenthesis

https://bugs.winehq.org/show_bug.cgi?id=47159

            Bug ID: 47159
           Summary: widl ignores calling convention when declaring
                    functions with extraneous parenthesis
           Product: Wine
           Version: 4.6
          Hardware: x86
                OS: Linux
            Status: UNCONFIRMED
          Severity: normal
          Priority: P2
         Component: rpc
          Assignee: wine-bugs(a)winehq.org
          Reporter: richard(a)torproject.org
      Distribution: ---

When declaring a __stdcall function foo like so widl discards the calling
convention attribute.

This snippet:

void (__stdcall foo)(void);

will generate:

void foo(void);

A bit of an edge case, looks like the parser grammar will need to be changed.
As a side effect, this snippet:

extern int (__stdcall someval);

will generate:

extern int someval;

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[Bug 47159] widl ignores calling convention when declaring functions with extraneous parenthesis

https://bugs.winehq.org/show_bug.cgi?id=47159

Zebediah Figura <z.figura12(a)gmail.com> changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
                 CC|                            |z.figura12(a)gmail.com

--- Comment #1 from Zebediah Figura <z.figura12(a)gmail.com> ---
(In reply to Richard Pospesel from comment #0)
> A bit of an edge case, looks like the parser grammar will need to be
> changed. As a side effect, this snippet:
>
> extern int (__stdcall someval);
>
> will generate:
>
> extern int someval;

I'm curious what this is supposed to mean, exactly? Presumably we should just
error out in this case. (Side note: MIDL actually does this too.)

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