9 Aug
2005
9 Aug
'05
5:49 a.m.
Hi, On Tue, Aug 09, 2005 at 01:32:51PM +0300, Saulius Krasuckas wrote:
* On Tue, 9 Aug 2005, Andreas Mohr wrote:
* On Tue, Aug 09, 2005 at 12:13:22PM +0300, Saulius Krasuckas wrote:
It if uninitialized memory in a case of MSVC and MSVCRTD, I guess. BUUUUG in the app. :-)
Yup, and AFAIR this gets initialized with 0x0c since that is a breakpoint instruction. But you possibly knew that already...
No, I didn't. Thanks.
Stupid me, despite my words it's still 0xcc, of course. INT 3 (breakpoint interrupt) call, AFAIR. Andreas