Not, if ref is 0 on the second last check. :3

R��mi Bernon <rbernon@codeweavers.com> schrieb am Fr., 22. Apr. 2022, 15:45:
Signed-off-by: R��mi Bernon <rbernon@codeweavers.com>
---

> @@ -1096,9 +1096,9 @@ static void test_SpeechRecognizer(void)
>�� �� �� �� �� ��ok(async_status == Completed, "Status was %#x.\n", async_status);
>�� ��
>�� �� �� �� �� ��ref = IAsyncInfo_Release(info);
> -�� �� �� �� ok(ref == 1, "Got unexpected ref %lu.\n", ref);
> +�� �� �� �� ok(ref >= 1, "Got unexpected ref %lu.\n", ref);
>�� �� �� �� �� ��ref = IAsyncOperation_SpeechRecognitionCompilationResult_Release(operation);
> -�� �� �� �� ok(!ref, "Got unexpected ref %lu.\n", ref);
> +�� �� �� �� ok(ref >= 0, "Got unexpected ref %lu.\n", ref);
>�� ��

Though I think this check is then useless.