Re: kernel32: quiet a noisy err (2/3)

[Vincent Povirk]

You're setting quieterr to 0 initially, and the if condition will only
be true if it is 1. The ERR will never be printed.

Also, I think you should move the test for quieterr into the for loop,
since all the loop does is print the ERR.

Vincent Povirk



On Thu, Oct 16, 2008 at 7:46 PM, Austin English <austinenglish(a)gmail.com> wrote:
> --
> -Austin