[PATCH vkd3d] vkd3d: Handle D3D12_APPEND_ALIGNED_ELEMENT for <4 byte wide elements

[Conor McCarthy]

In d3d12, input element alignment needs to be the _minimum_ of 4 and the size of
the type. See the D3D11 spec, section 4.4.6, which behaves similarly:
https://microsoft.github.io/DirectX-Specs/d3d/archive/D3D11_3_FunctionalSpec...

This is correctly taken into account when generating, e.g., the
vertex_buffer_stride_align_mask used for validation, but is not taken
into account when D3D12_APPEND_ALIGNED_ELEMENT is used to automatically
place input elements. Currently, vkd3d always assumes the alignment is
4.

This means that, for example, bytes or shorts should be packed tightly
together when D3D12_APPEND_ALIGNED_ELEMENT is used, but are instead
padded to 4 bytes.

Fixing this makes units appear in Age of Empires IV.

(CrossOver bug 19924).

From: David Gow <david(a)ingeniumdigital.com>
Signed-off-by: Conor McCarthy <cmccarthy(a)codeweavers.com>
---
 libs/vkd3d/state.c | 4 ++--
 1 file changed, 2 insertions(+), 2 deletions(-)

diff --git a/libs/vkd3d/state.c b/libs/vkd3d/state.c
index e51c11ea..847f497b 100644
--- a/libs/vkd3d/state.c
+++ b/libs/vkd3d/state.c
@@ -2807,9 +2807,9 @@ static HRESULT compute_input_layout_offsets(const struct d3d12_device *device,
         if (e->AlignedByteOffset != D3D12_APPEND_ALIGNED_ELEMENT)
             offsets[i] = e->AlignedByteOffset;
         else
-            offsets[i] = input_slot_offsets[e->InputSlot];
+            offsets[i] = align(input_slot_offsets[e->InputSlot], min(4, format->byte_count));
 
-        input_slot_offsets[e->InputSlot] = align(offsets[i] + format->byte_count, 4);
+        input_slot_offsets[e->InputSlot] = offsets[i] + format->byte_count;
     }
 
     return S_OK;
-- 
2.34.1