On Thu Oct 26 21:15:48 2023 +0000, Giovanni Mascellani wrote:
That's still going to be not pretty if there are three or more cases with the same value. I guess in this case we want to emit an error for each case starting from the second one, and a note pointing to the first one. So you'd rather iterate on the previous cases rather then on the following, and break out as soon as you emit an error.
I moved this around, it now checks against current list before adding a new case.