Not, if ref is 0 on the second last check. :3
Rémi Bernon rbernon@codeweavers.com schrieb am Fr., 22. Apr. 2022, 15:45:
Signed-off-by: Rémi Bernon rbernon@codeweavers.com
@@ -1096,9 +1096,9 @@ static void test_SpeechRecognizer(void) ok(async_status == Completed, "Status was %#x.\n",
async_status);
ref = IAsyncInfo_Release(info);
ok(ref == 1, "Got unexpected ref %lu.\n", ref);
ok(ref >= 1, "Got unexpected ref %lu.\n", ref); ref =
IAsyncOperation_SpeechRecognitionCompilationResult_Release(operation);
ok(!ref, "Got unexpected ref %lu.\n", ref);
ok(ref >= 0, "Got unexpected ref %lu.\n", ref);
Though I think this check is then useless.