Re: deliver full path by argv[0] and GetCommandLine for win9x

[Juan Lang]

--- Alexandre Julliard  wrote:
> No, the interesting case is what happens with
> CreateProcess. Launching
> the app from cmd.exe doesn't tell you anything,
> because you don't know
> exactly what arguments cmd.exe passed to
> CreateProcess.

You're right, as usual :)

I created another test case:
#include <windows.h>
#include <stdio.h>

int main(int argc, const char *argv[])
{
    if (argc <= 1)
    {
        PROCESS_INFORMATION procInfo;
        STARTUPINFO startInfo;

memset(&startInfo, 0, sizeof(startInfo));
        startInfo.cb = sizeof(startInfo);
        if (CreateProcessA(NULL, "cmdlinetest.exe 1",
NULL, NULL, FALSE,
         0, NULL, NULL, &startInfo, &procInfo))
        {
            CloseHandle(procInfo.hProcess);
            CloseHandle(procInfo.hThread);
        }
    }
    else
    {
        LPCSTR cmd;

printf("argv[0] is %s\n", argv[0]);
        cmd = GetCommandLineA();
        printf("GetCommandLine returns %s\n", cmd);
    }
    return 0;
}

With this, the output under win9x is:
argv[0] is cmdlinetest.exe
GetCommandLine returns cmdlinetest.exe 1

So, Frank, sorry, this isn't the way GetCommandLine
actually behaves under Win9x.
--Juan

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