12 Mar
2007
12 Mar
'07
3:29 a.m.
"Alexandre Julliard" julliard@winehq.org wrote:
The point is that (void*)0 isn't guaranteed to be represented by an all-zero bit pattern; but that's the case on any platform worth worrying about.
If (void*)0 doesn't guarantee to actually set all bits to 0, then HEAP_ZERO_MEMORY doesn't guarantee it either.
--
Dmitry.