Re: msvcrt: return wall-clock time from clock()

[Alexandre Julliard]

Daniel Lehman  writes:
> @@ -709,19 +711,26 @@ int CDECL _wstrtime_s(MSVCRT_wchar_t* time, MSVCRT_size_t size)
>   */
>  MSVCRT_clock_t CDECL MSVCRT_clock(void)
>  {
> - FILETIME ftc, fte, ftk, ftu;
> - ULONGLONG utime, ktime;
> -
> - MSVCRT_clock_t clock;
> - static LONGLONG start_time;
> - LONGLONG current_time;
> - struct timeval now;
> - GetProcessTimes(GetCurrentProcess(), &ftc, &fte, &ftk, &ftu);
> - if(!start_time) {
> -
>    KERNEL_USER_TIMES pti;
>
> - ktime = ((ULONGLONG)ftk.dwHighDateTime << 32) | ftk.dwLowDateTime;
> - utime = ((ULONGLONG)ftu.dwHighDateTime << 32) | ftu.dwLowDateTime;
> -
>    /* while Linux's clock returns user time, Windows' clock
> -
>     * returns wall-clock time from process start.  cache the
> -
>     * process start time since it won't change and to avoid
> -
>     * wineserver round-trip overhead */
> -
>    if(NtQueryInformationProcess(GetCurrentProcess(), ProcessTimes, &pti, sizeof(pti), NULL))
> -
>        return -1;
> -
>    start_time = pti.CreateTime.QuadPart;
> - }
> - clock = (utime + ktime) / (TICKSPERSEC / MSVCRT_CLOCKS_PER_SEC);
> - gettimeofday(&now, NULL);
> - current_time = (LONGLONG)now.tv_sec * TICKSPERSEC + now.tv_usec * 10 + TICKS_1601_TO_1970;

You should be using Windows APIs for this, not gettimeofday.