17 Oct
2008
17 Oct
'08
3:28 p.m.
You're setting quieterr to 0 initially, and the if condition will only be true if it is 1. The ERR will never be printed.
Also, I think you should move the test for quieterr into the for loop, since all the loop does is print the ERR.
Vincent Povirk
On Thu, Oct 16, 2008 at 7:46 PM, Austin English austinenglish@gmail.com wrote:
-- -Austin