On Fri, Oct 14, 2011 at 13:44, Jacek Caban jacek@codeweavers.com wrote:
dlls/vbscript/lex.c | 10 ++++++++++ dlls/vbscript/tests/lang.vbs | 7 +++++++ dlls/vbscript/tests/run.c | 2 ++ 3 files changed, 19 insertions(+), 0 deletions(-)
Hi, Jacek, I'm far away from my linux box and I'm just passing by to remember that there is a 24 continuation limit.
Here is an invalid operation because it has 26 continuations: x = _ 3 _ + 3 _ + 3 _ + 3 _ + 3 - _ 3 + _ 3 _ + 3 _ + 3 _ + 3 _ + 3 _ + 3 _ + 3 _ + 3 _ + 3 _ + 3 _ + 3 _ + 3 _ + 3 _ + 3 _ + 3 _ + 3 _ + 3 _ + 3 _ + 3 _ + 3
And this is another test that must pass too (there is no new operand after the last _ ) : x = _ 3 _ + 3 _ + 3 _ + 3 _
As I said I can't test in wine but maybe you will find this information useful.
Best wishes, Bruno
Hi Bruno,
On 10/14/11 20:07, Bruno Jesus wrote:
On Fri, Oct 14, 2011 at 13:44, Jacek Cabanjacek@codeweavers.com wrote:
dlls/vbscript/lex.c | 10 ++++++++++ dlls/vbscript/tests/lang.vbs | 7 +++++++ dlls/vbscript/tests/run.c | 2 ++ 3 files changed, 19 insertions(+), 0 deletions(-)
Hi, Jacek, I'm far away from my linux box and I'm just passing by to remember that there is a 24 continuation limit.
Here is an invalid operation because it has 26 continuations: x = _ 3 _
- 3 _
- 3 _
- 3 _
- 3 - _
3 + _ 3 _
- 3 _
- 3 _
- 3 _
- 3 _
- 3 _
- 3 _
- 3 _
- 3 _
- 3 _
- 3 _
- 3 _
- 3 _
- 3 _
- 3 _
- 3 _
- 3 _
- 3 _
- 3 _
- 3
I've tested it and that doesn't seem to be true.
And this is another test that must pass too (there is no new operand after the last _ ) : x = _ 3 _
- 3 _
- 3 _
- 3 _
This will work only if the next line is empty (exactly like my implementation does).
Jacek
Hi, Jacek.
On Mon, Oct 17, 2011 at 10:30, Jacek Caban jacek@codeweavers.com wrote:
Hi Bruno,
On 10/14/11 20:07, Bruno Jesus wrote: ... I've tested it and that doesn't seem to be true.
You're right, in a vbs file the limit does not exist, it looks like to be a Visual Basic 6 editor limit. Sorry for the noise.
And this is another test that must pass too (there is no new operand after the last _ ) : x = _ 3 _
- 3 _
- 3 _
- 3 _
This will work only if the next line is empty (exactly like my implementation does).
Great =)
Jacek
Best wishes, Bruno