Re: deliver full path by argv[0] and GetCommandLine for win9x

[Juan Lang]

Okay, here's a test program:
#include <windows.h>
#include <stdio.h>

int main(int argc, const char *argv[])
{
    LPCSTR cmd;

printf("argv[0] is %s\n", argv[0]);
    cmd = GetCommandLineA();
    printf("GetCommandLine returns %s\n", cmd);
    return strcmp(argv[0], cmd);
}

Under Windows 2000, cmd.exe, run from the current
directory, I get:
argv[0] is cmdlinetest.exe
GetCommandLine returns cmdlinetest.exe

Under Windows 2000, command.com, run from the current
directory, I get:
argv[0] is CMDLIN~1.exe
GetCommandLine returns CMDLIN~1.exe

Under Windows 2000, run from the debugger, I get:
argv[0] is c:\src\cmdlinetest\Debug\cmdlinetest.exe
GetCommandLineA returns
"c:\src\cmdlinetest\Debug\cmdlinetest.exe"
(This case is interesting because it shows argv[0] and
GetCommandLineA can be different even without
arguments.)

Under Windows ME, command.com, run from the current
directory, I get:
argv[0] is C:\SRC\CMDLIN~1\DEBUG\CMDLIN~1.EXE
GetCommandLine returns
C:\SRC\CMDLIN~1\DEBUG\CMDLIN~1.EXE

This is the same executable, so it isn't a different
_CRTMainStartup.  I think this supports Frank's
assertion.

--Juan

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deliver full path by argv[0] and GetCommandLine for win9x

[Alexandre Julliard]

Juan Lang  writes:
> This is the same executable, so it isn't a different
> _CRTMainStartup.  I think this supports Frank's
> assertion.

No, the interesting case is what happens with CreateProcess. Launching
the app from cmd.exe doesn't tell you anything, because you don't know
exactly what arguments cmd.exe passed to CreateProcess.

deliver full path by argv[0] and GetCommandLine for win9x

[Juan Lang]

--- Alexandre Julliard  wrote:
> No, the interesting case is what happens with
> CreateProcess. Launching
> the app from cmd.exe doesn't tell you anything,
> because you don't know
> exactly what arguments cmd.exe passed to
> CreateProcess.

You're right, as usual :)

I created another test case:
#include <windows.h>
#include <stdio.h>

int main(int argc, const char *argv[])
{
    if (argc <= 1)
    {
        PROCESS_INFORMATION procInfo;
        STARTUPINFO startInfo;

memset(&startInfo, 0, sizeof(startInfo));
        startInfo.cb = sizeof(startInfo);
        if (CreateProcessA(NULL, "cmdlinetest.exe 1",
NULL, NULL, FALSE,
         0, NULL, NULL, &startInfo, &procInfo))
        {
            CloseHandle(procInfo.hProcess);
            CloseHandle(procInfo.hThread);
        }
    }
    else
    {
        LPCSTR cmd;

printf("argv[0] is %s\n", argv[0]);
        cmd = GetCommandLineA();
        printf("GetCommandLine returns %s\n", cmd);
    }
    return 0;
}

With this, the output under win9x is:
argv[0] is cmdlinetest.exe
GetCommandLine returns cmdlinetest.exe 1

So, Frank, sorry, this isn't the way GetCommandLine
actually behaves under Win9x.
--Juan

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