You're setting quieterr to 0 initially, and the if condition will only be true if it is 1. The ERR will never be printed.
Also, I think you should move the test for quieterr into the for loop, since all the loop does is print the ERR.
Vincent Povirk
On Thu, Oct 16, 2008 at 7:46 PM, Austin English austinenglish@gmail.com wrote:
-- -Austin
On Fri, Oct 17, 2008 at 10:28 AM, Vincent Povirk madewokherd+8cd9@gmail.com wrote:
You're setting quieterr to 0 initially, and the if condition will only be true if it is 1. The ERR will never be printed.
Also, I think you should move the test for quieterr into the for loop, since all the loop does is print the ERR.
Vincent Povirk
On Thu, Oct 16, 2008 at 7:46 PM, Austin English austinenglish@gmail.com wrote:
-- -Austin
Whoops, sent the wrong one. Thanks for catching that. I'll resend shortly.